This is my LeetCode exercise.
You can see all question I did here.
leetcode
medium
Binary Search
Tree
Binary Tree
Depth_first Search
Given the $root$ of a complete binary tree, return the number of the nodes in the tree.
According to Wikipedia, every level, except possibly the last, is completely filled in a complete binary tree, and all nodes in the last level are as far left as possible. It can have between $1$ and $2^h$ nodes inclusive at the last level $h$.
Design an algorithm that runs in less than $O(n)$ time complexity.
Input: root = [1,2,3,4,5,6]
Output: 6
Input: root = []
Output: 0
Input: root = [1]
Output: 1
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
int countNodes(struct TreeNode* root){
if (root == NULL)
return 0;
if(!root->left && !root->right)
return 1;
return 1 + countNodes(root->left) + countNodes(root->right);
}
Space | Time |
---|---|
$O(1)$ | $O(n)$ |