This is my LeetCode exercise.
You can see all question I did here.
leetcode
easy
Array
We are given a list nums
of integers representing a list compressed with run-length encoding.
Consider each adjacent pair of elements [freq, val] = [nums[2*i], nums[2*i+1]]
(with i >= 0
). For each such pair, there are freq
elements with value val
concatenated in a sublist. Concatenate all the sublists from left to right to generate the decompressed list.
Return the decompressed list.
Input: nums = [1,2,3,4]
Output: [2,4,4,4]
Explanation: The first pair [1,2] means we have freq = 1 and val = 2 so we generate the array [2].
The second pair [3,4] means we have freq = 3 and val = 4 so we generate [4,4,4].
At the end the concatenation [2] + [4,4,4] is [2,4,4,4].
Input: nums = [1,1,2,3]
Output: [1,3,3]
nums.length % 2 == 0
int* decompressRLElist(int* nums, int numsSize, int* returnSize) {
int i, j, count = 0, set = numsSize / 2;
int* returnArray;
*returnSize = 0; // initial size
for (i = 0; i < set; i++) // count decompress size
*returnSize += nums[2 * i];
// memory allocation decompression space
returnArray = (int*)malloc(*returnSize * sizeof(int));
for (i = 0; i < set; i++) // double loop for value assign
for (j = 0; j < nums[2 * i]; j++, count++)
returnArray[count] = nums[2 * i + 1];
return returnArray;
}
Space | Time |
---|---|
$O(N)$ | $O(N)$ |